Force equations

118 views 11:06 am 0 Comments June 8, 2023

Question 1

15kg
rn2 = 25kg lm
Figure Q1
= 0.2m
Two masses on a pulley are initially held at rest and at the same height as shown on the left of figure Q1. Once the masses are released, mass m2 falls while mass mi rises. Upon dropping 1.0 m, mass mu falls further compressing a large spring by 0.2 m and then coming to a halt. (The pulley and connecting string are assumed massless)
a. Use force equations to prove the situation upon release, where m2 falling and m, rising is the correct outcome.
(3 marks) b. Using energy, determine the velocity of the masses just before mass mu starts to compress the spring.
(6 marks) c. Based on the maximum compressed length of the spring, 0.2m determine the spring constant, k.
(4 marks)
[Total 13 marks]

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